原始问题:
"完美数字统计:计算数组中各数字出现次数"
好的,我可以帮你统计数字出现的次数并计算完美数字的个数。你可以将数字列表输入给我,然后我会进行处理。
以下是一个示例代码,用于统计数字出现的次数并计算完美数字的个数:
def count_occurrences(numbers):
occurrences = {}
perfect_count = 0
for num in numbers:
if num in occurrences:
occurrences[num] += 1
else:
occurrences[num] = 1
for count in occurrences.values():
if count == num:
perfect_count += 1
return perfect_count
numbers = [1, 2, 2, 3, 3, 3]
perfect_count = count_occurrences(numbers)
print("完美数字的个数:", perfect_count)你可以将你的数字列表替换掉numbers变量,然后运行代码即可得到完美数字的个数。希望对你有帮助!如果有任何问题,请随时提问。
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