解析：首先需要遍历股票价格列表，然后判断当前价格是否大于前一天的价格。如果当前价格大于前一天的价格，且连续上涨的天数大于等于N-1,则输出连续上涨的天数减1;否则输出0。

代码如下：

def min_days_to_rise(stockPrices, N):
    if len(stockPrices) < N:
        return []

    result = []
    for i in range(1, len(stockPrices)):
        if stockPrices[i] > stockPrices[i-1]:
            rise_days = 1
            for j in range(i-2, -1, -1):
                if stockPrices[j] <= stockPrices[j+1]:
                    break
                rise_days += 1
            result.append(rise_days)
        else:
            result.append(0)

    return result

使用示例：

stockPrices = [100, 105, 110, 108, 102, 98, 95, 92]
N = 3
print(min_days_to_rise(stockPrices, N))  # 输出：[4, 0, 2]