解析：首先需要定义一个二叉树节点类，包含值、左子节点和右子节点。然后根据输入的节点个数n,创建一个二叉树。接着根据输入的根节点和颜色信息，构建二叉树。最后计算根节点的值并输出。

代码如下：

#include <stdio.h>
#include <stdlib.h>

typedef struct TreeNode {
    int val;
    struct TreeNode *left;
    struct TreeNode *right;
} TreeNode;

TreeNode* createNode(int val) {
    TreeNode *node = (TreeNode *)malloc(sizeof(TreeNode));
    node->val = val;
    node->left = NULL;
    node->right = NULL;
    return node;
}

void buildTree(TreeNode **root, int *p, int n, int c[]) {
    if (p[0] == -1) return;
    (*root) = createNode(p[0]);
    int left_count = 0, right_count = 0;
    for (int i = 1; i < n; i++) {
        if (p[i] == p[0]) left_count++;
        else if (p[i] == p[0]) right_count++;
    }
    int left_val = c[p[0]];
    int right_val = c[p[0]];
    int left_index = -1, right_index = -1;
    for (int i = 1; i < n; i++) {
        if (c[p[i]] == left_val) left_index = i;
        else if (c[p[i]] == right_val) right_index = i;
    }
    int left_parent = p[0], right_parent = p[0];
    int left_color = c[left_parent], right_color = c[right_parent];
    int left_child = p[left_index], right_child = p[right_index];
    (*root)->left = buildTree(&((*root)->left), p + left_count, n, c);
    (*root)->right = buildTree(&((*root)->right), p + left_count + right_count, n, c);
}

int getRootValue(TreeNode *root) {
    if (root == NULL) return 0;
    int left_val = getRootValue(root->left);
    int right_val = getRootValue(root->right);
    int color = root->left != NULL && root->right != NULL ? "red" : "blue";
    int result = root->val;
    if (color == "red") result *= left_val;
    else result += right_val;
    return result;
}

int main() {
    int n;
    scanf("%d", &n);
    int *p = (int *)malloc(n * sizeof(int));
    int *c = (int *)malloc(n * sizeof(int));
    p[0] = n > 1 ? scanf("%d", &p[1]) : -1;
    c[n > 1] = scanf("%d", &c[n > 1]);
    p++; c++;
    memset(p, -1, (n + 1) * sizeof(int)); memset(c, 0, n * sizeof(int));
    int root_value = getRootValue(createNode(0)); printf("%d  
", root_value); free(p); free(c); free(createNode(0)); return 0;
}