解析：首先需要遍历数组，找到所有的完美数。然后再遍历完美数，找到所有与之相乘为完美数的元素对。最后计算这些元素对的数量。

代码如下：

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int[] arr = new int[n];
        for (int i = 0; i < n; i++) {
            arr[i] = sc.nextInt();
        }
        sc.close();

        int count = 0;
        for (int i = 0; i < n; i++) {
            if (isPerfectNumber(arr[i])) {
                for (int j = 0; j < n; j++) {
                    if (arr[j] != 0 && isPerfectNumber(arr[i] * arr[j])) {
                        count++;
                    }
                }
            }
        }
        System.out.println(count);
    }

    public static boolean isPerfectNumber(int num) {
        int sum = 0;
        while (num > 0) {
            int digit = num % 10;
            if (digit != 0) {
                sum += digit;
            }
            num /= 10;
        }
        return sum == num;
    }
}